User:Rossolson/Math/HTML and CSS

From: gutenberg.org/ebooks/57359/ - Page 463

CSS:

.displaystyle {
    display: inline-block;
    position: relative;
    vertical-align: middle;
    font-size: 150%
    }
.equation {
    text-align: center;
    padding-bottom: 1ex
    }
span.frac {
    display: inline-block;
    position: relative;
    vertical-align: middle;
    font-size: 80%;
    text-align: center
    }
span.frac > sup {
    display: block
    }
span.frac > span {
    display: none
    }
span.frac > sub {
    display: block;
    border-top: thin solid black
    }
span.dfrac {
    display: inline-block;
    position: relative;
    vertical-align: middle;
    font-size: 120%;
    text-align: center
    }
span.dfrac > sup {
    display: block
    }
span.dfrac > span {
    display: none
    }
span.dfrac > sub {
    display: block;
    border-top: thin solid black
    }
.fnmark {
    vertical-align: super;
    font-size: smaller
    }
.fntext {
    font-size: smaller
    }

<p>

The difficulty felt by most students is in applying the formula to actual statistics, in other words in putting in the correct units. To take an actual numerical example, suppose that 1460 men have been measured in regard to their height “true to the nearest inch,” and let it be known that the modulus here is 3.6 inches. Then <i>dx</i> = 1 (inch); <i>h</i>⁻¹ = 3.6 inches.

Now ∑<span class="frac">^<i>h</i><span>/</span>_√π</span><i>e</i>^{−<i>h</i>²<i>x</i>²}<i>dx</i> = 1; that is, the sum of all the consecutive possible values is equal to unity. When therefore we want the sum, as here, to be 1460, we must express the formula thus;—

<i>y</i> = <span class="frac">¹⁴⁶⁰<span>/</span>_{√π <i>×</i> 3.6}</span> <i>e</i>^{−(<span class="frac">^<i>x</i><span>/</span>_3.6</span>)²}, or <i>y</i> = 228<i>e</i>^{−(<span class="frac">^<i>x</i><span>/</span>_3.6</span>)²}.

</p>